2 tex edited Apr 1 '14 at 3:01 Chris Cunningham♦ 10.9k55 gold badges4242 silver badges102102 bronze badges I like this one,for promoting a sense of awe and wonder..and inquiry: there is a 'gap' in the graph of the function - obviously at x=1 - of y = ( n$$n=1$$, of / n-1)^n$$y = \big(\frac{n}{n-1}\big)^n$$..since. since it is a gap,it it must be able to be 'bridged' you would think,but but since it also is a gap of zero dimensions it can't be: it both can and can't 'exist' simultaneously..it's it's 'there'..but but when we try to measure it in physical terms..it's it's not! I like this one,for promoting a sense of awe and wonder..and inquiry: there is a 'gap' in the graph of the function - obviously at x=1 - of y = ( n / n-1)^n..since it is a gap,it must be able to be 'bridged' you would think,but since it also is a gap of zero dimensions it can't be: it both can and can't 'exist' simultaneously..it's 'there'..but when we try to measure it in physical terms..it's not! I like this one,for promoting a sense of awe and wonder..and inquiry: there is a 'gap' in the graph of the function - obviously at $$n=1$$, of $$y = \big(\frac{n}{n-1}\big)^n$$... since it is a gap, it must be able to be 'bridged' you would think, but since it also is a gap of zero dimensions it can't be: it both can and can't 'exist' simultaneously.. it's 'there'.. but when we try to measure it in physical terms.. it's not! 1 answered Apr 1 '14 at 2:30 Neil 1 I like this one,for promoting a sense of awe and wonder..and inquiry: there is a 'gap' in the graph of the function - obviously at x=1 - of y = ( n / n-1)^n..since it is a gap,it must be able to be 'bridged' you would think,but since it also is a gap of zero dimensions it can't be: it both can and can't 'exist' simultaneously..it's 'there'..but when we try to measure it in physical terms..it's not!