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Feb 11, 2018 at 16:55 comment added Kevin The other option is to use the projective reals instead of the extended reals, because then you have $\infty = - \infty$ and $y=\frac{1}{x}$ is continuous.
Jan 15, 2018 at 19:31 comment added user797 (also, I find the $x/0$ form a particularly sensitive issue, since one of the common errors students make computing limits is ignoring the sign on the denominator when it converges to zero)
Jan 15, 2018 at 19:25 comment added user797 @DanielR.Collins: Yes, something has to be lost, but losing continuity is a poor poison to pick, since it sours one of the major applications of the number system: they simplify the computation of limits by continuously extending the operations involved. I'm not sure what you were getting at with your last sentence, but note that $\infty / 1 = \infty$ and there are a number of other values we need to leave undefined as well.
Jan 15, 2018 at 18:06 comment added Daniel R. Collins @Hurkyl: Extended reals aren't a field, so any way you cut it something gets lost (pick your poison, basically). The alternative is to not have division be onto the whole set under discussion.
Jan 15, 2018 at 16:08 comment added user797 @DanielR.Collins: That's an unusual convention, since it would mean division is not continuous on its domain; usually $1/0$ is left undefined, for the reason of this answer. Although one can conceive of a "positive zero", so that they can write $x/0^+ = \infty$.
Jan 13, 2018 at 23:35 comment added Daniel R. Collins One caveat would be this opens up a counterargument of inspecting $1/|x|$, say. Second caveat is when I see extended reals defined (i.e., $\infty$ as a usable number), it actually is defined that $x/0 = sgn(x) \cdot \infty$ (assuming $x \ne 0$; Ray, Real Analysis, Appendix A).
Jan 13, 2018 at 20:01 history answered Sue VanHattum CC BY-SA 3.0