6
$\begingroup$

I'm teaching algebra to lower ability grade 11 students. I've tried to give them fair grounding in algebraic manipulation. I'm trying to explain how to solve a linear equation like $2 x +1 =3$ (or $- 2.3 x + 1.2 =-3.7 $ but I'll treat the simpler one). The first step is clear "do the opposite of plus $1$" ie "subtract $1$ from both sides": $$ 2x+1=3 \\ 2x+1-1=3-1 \\ 2x+0=2 \\ 2x=2 $$ The middle steps are quite intuitive and my students seem happy skip them.

Next it comes to "do the opposite of multiply by $2$" ie "divide by 2" $$ \frac{2x}{2}=\frac22 \\ x=1. $$

How do I explain this step?

Ideas:

  1. $\frac{x+x}2=x$
  2. $\frac{2x}{2}=\frac22x=1x=x$
  3. $\frac{2x}{2}=x\frac22=x1=x$
  4. other explanations

I'll appraise these explanations.

  1. seems intuitive but won't easily handle the complex example above.
  2. The obvious choice, but why is it obvious and why is it true? Would I say that $\frac{a \times b}c = \frac{a}{c} \times b $? This seems confusing.
  3. exchanges "$2$ lots of $x$" with "$x$ lots of $2$", which is valid but seems confusing.
$\endgroup$
11
  • 3
    $\begingroup$ I just say "undo what is being done to $x$". Since $x$ is being multiplied by $2,$ you undo this by dividing by $2.$ There's also my shoe and sock analogy when more than one operation is involved. You PUT ON your sock, then PUT ON your shoe. To undo this 2-step process, perform the reverse operations in the reverse order --- you TAKE OFF your shoe, then TAKE OFF your sock. $\endgroup$ Mar 23, 2018 at 22:43
  • 1
    $\begingroup$ (2x)/2=2/2 x=1 (Also, I would emphasize to the students that you have to do equal actions to each side of the equation. If they are struggling with dividing ax=b (and also since you said they are lower ability and old), I think this is not the time to skip steps on add/subtract even if they know how to do them. I was a high ability 7th grader when I learned this stuff but my teacher was very rigorous about the step by step solving of the equations. Obviously in later math courses, one can relax this. But when first learning (or for kids who struggle), you need to keep the step by step. $\endgroup$
    – guest
    Mar 23, 2018 at 22:46
  • 1
    $\begingroup$ Agreed: do the same thing to both sides and don't skip steps. But how to explain $2x/2=x$ or $-2.3x/-2.3=x$? $\endgroup$
    – pdmclean
    Mar 23, 2018 at 23:12
  • 1
    $\begingroup$ If a student is to learn basic algebra, they have to have three things going for them: (1) competent instruction, (2) a sufficient genetic endowment, and (3) willingness to put in the effort. This is not so different from many other skills, such as playing the piano. Competent instruction doesn't mean you have to be a superhero. If you provide them with some reasonable explanation, like Dave Renfro's "undo what is being done to $x$," then that's competent instruction. It seems very unlikely to me that pedagogical details like the ones you're worrying about will make any difference. $\endgroup$
    – user507
    Mar 25, 2018 at 22:59
  • 1
    $\begingroup$ If they are having difficulty with this, then I would suggest the real problem is an issue with cancelling in fractions in general. I would get rid of the $x$ and just do a bunch of problems cancelling actual numbers. Most problems students have with Algebra wind up being a problem that they are actually having in arithmetic that was never cleared up for them. Once arithmetic is solid, then the algebra goes from difficult to easy. $\endgroup$
    – johnnyb
    Mar 26, 2018 at 20:50

2 Answers 2

4
$\begingroup$

I recommend that you carefully read the first part of the algebra book you use for your course. Usually there is a section on "Properties of Real Numbers", which effectively presents the axioms for the field structure of real numbers, and hence your course. Usually these are: (1) commutativity (add & multiply), (2) association (add & multiply), (3) distribution (multiply over add), (4) identities (add & multiply), (5) inverses (add & multiply).

Also there will be a formal definition of subtraction: $a - b = a + (-b)$, and division: $\frac{a}{b} = a \cdot \frac{1}{b}$. (Without saying this would be my top choice for axiomatic fundamentals, it is very standard.)

First note that properties of equivalent equations can be proven by basic properties of how equality is defined. E.g., For multiplication: If $a = b$, then $ac = bc$. Proof: $ac = ac$ by reflexivity; so $ac = bc$ by substitution ($a = b$ on right). Likewise for other operations.

Now, if desired, we can step through solving $2x = 2$ by the fundamental axioms. $\frac{2x}{2} = \frac{2}{2}$ by the equivalent-equation principle (prior paragraph, for division). This is equivalent to saying $2x \cdot \frac{1}{2} = 2 \cdot \frac{1}{2}$, by the definition of division. The left hand side is equivalent to $x \cdot 2 \cdot \frac{1}{2}$ (commutativity of multiplication), which is equal to $x \cdot 1$ (inverse property of multiplication), which is just $x$ (identity property of multiplication). The right hand side is immediately equal to $1$ (inverse property of multiplication). And so we have our $x = 1$.

Obviously, how much of these details you walk through with your students is up to you. Somewhat against popular opinion, I do actually find value and traction in my courses to walk through the axiomatic steps at least on one day, quizzing the class as a whole for which fundamental property was used at each step (as long as one or more students can give the answers in this presentation, I think it at least gives a model for everyone what real math looks like).

Ideally, of course, your students start generating an intuition that division to both sides of an equation cancels any multiplication there, as they did for the addition problem. The main problem I think we encounter is if they've previously been trained for addition problems to "move a term across the sides and change the sign", then that puts them on an incorrect path for any other operations.

$\endgroup$
4
  • 3
    $\begingroup$ The question says "grade 11". Are you sure that it's in a context which has an algebra book (as opposed to a single "mathematics" book) and has introduced the concept of axioms? $\endgroup$ Mar 26, 2018 at 8:37
  • 2
    $\begingroup$ @PeterTaylor: As stated in the answer, they won't call them axioms, they'll call them "Properties of Real Numbers". $\endgroup$ Mar 26, 2018 at 10:29
  • $\begingroup$ Regarding $\frac{a}{b}$ "defined" as $a \frac{1}{b}$: how do you define $\frac{1}{b}$?? $\endgroup$
    – Stef
    Sep 6, 2022 at 12:55
  • 1
    $\begingroup$ @stef: It's a number that satisfies the relation $b \times {1 \over b} = 1$. See here under "inverse property of multiplication". Note that's used above when we say $2 \times {1 \over 2}$ is the same as $1$: that's the definition of what $1 \over 2$ means. $\endgroup$ Sep 7, 2022 at 14:16
0
$\begingroup$

@Pdmclean, My answer is a perspective :

Keeping it simple while comprehensive would work, but it needs time. Sometimes, trying really hard to explain a concept will end up confusing the students.

Keeping it simple, compact, and firm may let the students understand it and to them the concept is actually simple, logical, and easier to grasp.

Build through habits and repetition, I remember a quote from a mathematician, which i think that it is quite true, it is something like this :

"In mathematics, you don't understand things. You just get used to them."

This is quite makes sense, because mathematics is a tool that we have created, a logical way of using numbers and symbols.


Example of explanation :

Solve $$2x + 1 = 4$$ The equation states that the value in left-hand side is equal to the value in right-hand side. If we change the value of either side, of course the equality will not apply anymore. So what we can do in order to get $$ x = .... (\text{something}) ? $$ To do this, manipulate each side the same way, adding or subtract by a number, divide or multiply by a number :

$$ 2x + 1 = 4 \implies 2x = 3 .....(\text{subtract by} -1)$$

Now what can we do to get the equation $x = \text{a number}$? divide both side by $2$.

$$ 2x = 3 \implies x = \frac{3}{2} .....(\text{divide by} 2) $$

*NOTICE that you can also do it by multiply by $\frac{1}{2}$


After this, repeat with different examples, or same one with different manipulation.

Try to solve only one problem on the board, with the students watching. Then repeat this steps several times, to 5-6 problems. (like watching a video, but the difference is they can ask directly to you)

After this, students must try to solve problems themselves, give them time 10-15 minutes. If they cannot, do the previous step for this particular problem only. This way, after the students have tried working on it, they now know in which part they made mistakes, and therefore know how to fix.


The key is that make the students get used to it, then the logic will eventually come to them.

$\endgroup$
2
  • $\begingroup$ The quotation that you have in mind (attributed to John von Neumann) is discussed a bit on MSE here. Whether this quotation from JvN applies well to the case of solving for all $x$ satisfying $2x = 2$ I cannot say. As to your answer, I'm not quite sure about your suggestions towards the end. (E.g., 10-15 minute time-frame.) Are these ideas based on... your own teaching? literature on teaching? ideas about teaching based on having been a student? other? $\endgroup$ Mar 25, 2018 at 17:51
  • $\begingroup$ @BenjaminDickman i have tried it in private tutoring for two senior high students, with the exactly same subject (solving linear equation). After around 7-8 repetition, they can independently solve a problem (they were underperforming in math, in final year but still cannot solve a linear eqn). Imagine oneself being in the student's position, with 10 minutes they tried to solve one problem..then if cannot..they watch me performing on the board slowly with explanation. Repeat this. So it is like an effort-feedback repetition, with one type of problem perday. $\endgroup$
    – Redsbefall
    Mar 25, 2018 at 18:09

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge that you have read and understand our privacy policy and code of conduct.

Not the answer you're looking for? Browse other questions tagged or ask your own question.