$A\cap B$ is not true or false; but it is true that the intersection of two disjoint sets is the empty set, that is, that $A\cap B = \varnothing$ is true. This comes down to a question about whether A\cap B is a boolean statement (a proposition): that which can be answered with "true or false". Asking if $A\cap B$ is true or false is no different than asking if 2+3 is true or false.
I think your presentation to the students invites such confusion. Why not draw two sets, $A, B,$ on the blackboard, disjoint, and ask $A\cap B = ?.$ By your own description, drawing two disjoint sets, A, B, and then writing $A\cap B$, and then asking "true or false" (without the option "neither true nor false") sets the students up for "failure", as you measure it. –
Among sets, we are able to know decisively, when given sets A, B the following boolean statements are such that they are always either true or false:
- $|A|>|B|, |A|< |B|,$ or $|A| = |B|$
- $A\subset B, B\subset A, \text{ or } A = B$.
In arithmetic we get boolean statements when we compare of equate numbers:
- $5+8 = 13$ (true)
- $8<5$ (false)
- The set of real numbers is a subset of the set of rational numbers. (false).
On the contrary,
- $5+8$
- $3x^2-4$
- $\frac{d}{dx} (8x-4 - x^2)$
Are not in the category of sentences that be be deemed true or false.
$A=\{1, 3, 5, 7, 9\}; B=\{2, 4, 6, 8, 10\}$. Then $A\cap B = \varnothing$, and is a true statement, whereas $A \cup B = \{1, 2, 3, 4, 5, 6, 7, 8, 9, 10\}$, which is also a true statement. But merely writing $A\cap B$, $A\cup B$ yields no sentence with a truth-value, and hence to ask if either is true or false misleads.
I think what is most misleading about the set of your friend is what appears to be an abuse of notation.
Let's partition the set of positive integers, which I refer to as $\mathbb N,$ into two sets:
- Let $A=\{2n-1\mid n \in \mathbb N\}$;
- Let $B= \{2n\mid n \in \mathbb N\}$.
Suppose your friend then writes below these sets: $$A\cap B$$
And then asks "True or False ?". The only way such a question has meaning is if the teacher is abusing the notation $A\cap B$ (which denotes the intersection between sets A and B), to mean "Is the intersection between A and B nonempty"? That's not what $A\cap B$ in fact means.