When teaching addition and multiplication of fractions, I seem to recall some advice on this site that one should first treat the cases
$a \cdot \frac{c}{d}$ and $a + \frac{c}{d}$ before moving on to the more general $\frac{a}{b} \cdot \frac{c}{d}$ and $\frac{a}{b} + \frac{c}{d}$.
This made think about the case $a \cdot \frac{1}{b}$ first. I would like to demonstrate in some way, and preferably (but not necessarily) geometrically, that $\frac{a}{b} = a \cdot \frac{1}{b}$, but I am having trouble finding an actual difference between $a \cdot \frac{1}{b}$ and $\frac{a}{b}$.
Of course, the answer might just be that $\frac{a}{b}$ and $a \cdot \frac{1}{b}$ have the same representation, and therefore they are equal.
Question:
Is there an agreed upon difference between how we represent $\frac{a}{b}$ and $a \cdot \frac{1}{b}$?