Timeline for Redundant zeros
Current License: CC BY-SA 3.0
5 events
| when toggle format | what | by | license | comment | |
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| Apr 10, 2014 at 20:33 | history | edited | Benjamin Dickman | CC BY-SA 3.0 |
added in screen-shot for convenience
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| Apr 3, 2014 at 9:54 | comment | added | Benjamin Dickman | @metacompactness My guess is Wu would write $0.50 = \frac{50}{100} = \frac{5 \times 10}{10 \times 10} = \frac{5}{10} = 0.5$, but this relies on a familiarity with the earlier material as he has set it up. Note that he is decomposing a product and then using a cancellation law, whereas you rewrote it as a sum, i.e., $0.50 = \frac{5}{10} + \frac{0}{100}$, etc. | |
| Apr 3, 2014 at 9:45 | comment | added | user5402 | Thanks for the references, but H.H. Wu's method is just what I showed in my question. I don't want a proof of this fact (I already proved it), I want them to understand it. Like understanding why $4\times 7=7\times 4$, you don't need an axiomatic approach, you just need some examples and maybe analogies. | |
| Apr 2, 2014 at 22:51 | history | edited | Benjamin Dickman | CC BY-SA 3.0 |
added 97 characters in body
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| Apr 2, 2014 at 22:46 | history | answered | Benjamin Dickman | CC BY-SA 3.0 |