Timeline for How to explain to a ~$12-16$ year-old student who is weak at maths, that $\ 38 \times 27 \times 14 = 27 \times 14 \times 38$?
Current License: CC BY-SA 4.0
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| Dec 13, 2022 at 13:13 | comment | added | Steve | As an aside commenting on whether this answer truly meets the other, overall need of helping the student achieve proficiency in addition to understanding, I am not sure the difference between a student who can successfully recognize the applicability of the commutative law and apply it and one who cannot is that the former has a very clear justification of why this can be done for an arbitrary number of factors. | |
| Dec 13, 2022 at 13:11 | history | answered | Steve | CC BY-SA 4.0 |